5/(2x-2)=2/(x^2-1)

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Solution for 5/(2x-2)=2/(x^2-1) equation:


D( x )

2*x-2 = 0

x^2-1 = 0

2*x-2 = 0

2*x-2 = 0

2*x-2 = 0 // + 2

2*x = 2 // : 2

x = 2/2

x = 1

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

5/(2*x-2) = 2/(x^2-1) // - 2/(x^2-1)

5/(2*x-2)-(2/(x^2-1)) = 0

5/(2*x-2)-2*(x^2-1)^-1 = 0

5/(2*x-2)-2/(x^2-1) = 0

(5*(x^2-1))/((2*x-2)*(x^2-1))+(-2*(2*x-2))/((2*x-2)*(x^2-1)) = 0

5*(x^2-1)-2*(2*x-2) = 0

5*x^2-4*x-1 = 0

5*x^2-4*x-1 = 0

5*x^2-4*x-1 = 0

DELTA = (-4)^2-(-1*4*5)

DELTA = 36

DELTA > 0

x = (36^(1/2)+4)/(2*5) or x = (4-36^(1/2))/(2*5)

x = 1 or x = -1/5

(x+1/5)*(x-1) = 0

((x+1/5)*(x-1))/((2*x-2)*(x^2-1)) = 0

((x+1/5)*(x-1))/((2*x-2)*(x^2-1)) = 0 // * (2*x-2)*(x^2-1)

(x+1/5)*(x-1) = 0

( x+1/5 )

x+1/5 = 0 // - 1/5

x = -1/5

( x-1 )

x-1 = 0 // + 1

x = 1

x in { 1}

x = -1/5

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